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Exam CPA-21-02 All Questions

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Exam CPA-21-02 topic 1 question 1 discussion

Actual exam question from C++ Institute's CPA-21-02
Question #: 1
Topic #: 1
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

  • A. It prints: 4
  • B. It prints: 1
  • C. It causes a compilation error
  • D. It prints: 0
Show Suggested Answer Hide Answer
Suggested Answer: D 🗳️
by NiceKing at Dec. 30, 2023, 1 a.m.

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Chosen Answer:
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FetaHillaryDelu
5 months, 2 weeks ago
Selected Answer: C
error: expected declaration before ‘}’ token error: expected ‘]’ before ‘return’
upvoted 1 times
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Fadil_Bxl
8 months ago
Selected Answer: C
main function gives error because of brackets not correct. [} in stead of {}
upvoted 1 times
Fadil_Bxl
8 months ago
error: expected declaration before ‘}’ token error: expected ‘]’ before ‘return’
upvoted 1 times
...
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MitMik97
9 months ago
Selected Answer: D
#include <iostream> using namespace std; int fun(int x){ return 4 * x; } int main(){ cout << fun(0) && fun(1); return 0; }
upvoted 1 times
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Mullets8818
1 year, 1 month ago
Selected Answer: C
The correct answer is C because the opening brace for the body of main was mis-typed as a bracket.
upvoted 2 times
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Omar_Alesharie
1 year, 4 months ago
Selected Answer: D
As NiceKing says foo(0) && foo(1) would evaluate to 0 && 4 with 4 implicitly converted to 1 for a logical && operation. The result of 0 would output as int.
upvoted 1 times
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Miguel85
1 year, 9 months ago
fun(0) && fun(1) is FALSE. but even if it were TRUE would it still be a syntax error because there is no condition (like an IF ) to check for TRUE or FLASE ?
upvoted 1 times
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NiceKing
1 year, 11 months ago
Selected Answer: D
foo(0) && foo(1) would evaluate to 0 && 4 with 4 implicitly converted to 1 for a logical && operation. The result of 0 would output as int.
upvoted 3 times
...
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