Exam 1z0-829 topic 1 question 83 discussion

Actual exam question from Oracle's 1z0-829

Question #: 83
Topic #: 1

Given the code fragment:

LocalDate now = LocalDate.now();
LocalDate this_labourDay = LocalDate.of(2021, Month.MAY, 1); LocalDate next_labourDay = this_labourDay.plusYears(1);
LocalDate add_week = next_labourDay.plusDays(7);
Period p = now.until(add_week);
System.out.println(p);

Assume LocalDate.now() returns 17th Aug 2021.

What is the result?

A. 21D8M
B. P8M21D
C. 08-MAY-2022
D. 1Y0M7D

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Suggested Answer: B 🗳️

by unix105 at Nov. 4, 2025, 12:11 a.m.

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unix105

3 weeks, 2 days ago

Selected Answer: B

start date: 8/17/2021 end date: 5/8/2022 days difference: * perform (end day - start day): 8 - 17 * if end day is less than start day, borrow numbers of days in previous month of end day * April has 30 days add that to end day (8 + 30 = 38) * then re-perform (end day - start day): 38 - 17 = 21 * adjusted end date is: 4/8/2022 months difference: * perform (end month - start month): 4 - 8 * if end month is less than start month, borrow 12 months in the previous year of end month * 2021 is end's month previous year then we add its 12 months (4 + 12 = 16) * then re-perform (end month - start month): 16 - 8 = 8 * adjusted end date is 4/8/2021 year difference: * performed (end year - start year): 2021 - 2021 = 0 * result: P8M21D

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