If the file is named 'existing_file' (with underscore), but Python tries to open 'existing file' (with space), then:
There is no such file.
But the mode is 'w' → write mode.
Write mode does not care if the file exists — it just creates a new one if missing.
So no error happens.
Python will silently create a new empty file named 'existing file'.
Hence, the output will still be:
1 3
The try block executes successfully as the file exists and is opened in write mode.
The code prints 1 from the try block and 3 from the else block, resulting in the output 1 3.
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