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Exam NCA v6.10 All Questions

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Exam NCA v6.10 topic 1 question 10 discussion

Actual exam question from Nutanix's NCA v6.10
Question #: 10
Topic #: 1
[All NCA v6.10 Questions]

An administrator is configuring Erasure Coding on a Redundancy Factor 2 cluster.
How many nodes, at a minimum, are necessary?

  • A. 3
  • B. 4
  • C. 5
  • D. 6
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Suggested Answer: B 🗳️

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43eb284
3 months, 1 week ago
Selected Answer: B
ChadGPT: Erasure Coding (EC) in Nutanix requires more nodes than simple replication because data is striped across nodes with parity blocks for fault tolerance. In a Redundancy Factor 2 (RF2) cluster, the cluster can tolerate one node failure. For Erasure Coding with RF2, Nutanix requires a minimum of 4 nodes. With fewer than 4 nodes, the system cannot properly distribute data and parity blocks while still maintaining resiliency. The 4-node minimum ensures there are enough nodes to hold the data stripes and parity information across the cluster.
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tch
3 months, 2 weeks ago
Selected Answer: B
A cluster must have at least four nodes/blocks/racks to enable erasure coding. The cluster can have all four flash nodes or a combination of flash and hybrid nodes, or all hybrid nodes. If erasure coding is enabled on a storage container, a minimum of four blocks for RF2 or six blocks for RF3 is required to maintain block awareness. check this link: https://portal.nutanix.com/page/documents/details?targetId=Prism-Central-Guide-vpc_2024_2:wc-erasure-coding-best-practices-requirements-wc-c.html
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nvg75
3 months, 3 weeks ago
Selected Answer: A
RF2 + EC → min 3 nodes RF3 + EC → min 5 nodes
upvoted 1 times
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tch
3 months, 3 weeks ago
Selected Answer: B
should be 4 ?
upvoted 2 times
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